How do you calculate expected shortfall from a loss distribution, and why is it preferred over VaR?
I know expected shortfall (ES or CVaR) answers 'given that we exceeded VaR, what's the average loss?' But I'm unsure how to actually compute it from a discrete loss distribution versus a continuous normal distribution. The FRM exam tests both approaches. Can you walk through the calculations?
Expected shortfall (ES), also called conditional VaR (CVaR), measures the average loss in the tail beyond VaR. It answers the question: 'When things go bad, how bad on average?' This makes it strictly more informative than VaR, which only identifies the threshold.\n\nContinuous Normal Distribution:\n\nFor a normal distribution N(mu, sigma) at confidence level alpha:\n\nES_alpha = mu + sigma x phi(z_alpha) / (1 - alpha)\n\nwhere phi(z) is the standard normal PDF evaluated at z_alpha.\n\nAt 99% confidence (z = 2.326):\nphi(2.326) = 0.02656\nES multiplier = 0.02656 / 0.01 = 2.656\n\nCompare: VaR multiplier = 2.326. So ES is about 14% higher than VaR for normal distributions at 99%.\n\nDiscrete Distribution Calculation:\n\nSuppose Northfield Capital has 1,000 historical daily P&L observations sorted from worst to best. At 95% confidence, VaR is the 50th worst loss.\n\nES(95%) = average of the 50 worst losses\n\n| Rank | Loss ($M) |\n|---|---|\n| 1 (worst) | -8.20 |\n| 2 | -7.45 |\n| 3 | -6.90 |\n| ... | ... |\n| 48 | -3.15 |\n| 49 | -3.08 |\n| 50 | -2.95 |\n\nVaR(95%) = $2.95M (the 50th observation)\nES(95%) = average of losses 1 through 50 = $4.62M (hypothetical average)\n\nES captures how the worst losses are distributed in the tail, while VaR only identifies the boundary.\n\nWhy ES Is Preferred:\n\n1. Coherence: ES is a coherent risk measure (satisfies subadditivity). VaR can paradoxically show that merging two portfolios increases risk, violating diversification logic.\n\n2. Tail sensitivity: Two portfolios with identical VaR can have vastly different ES if one has a heavier tail.\n\n3. Regulatory adoption: Basel III/IV uses ES (97.5%) for market risk capital under FRTB.\n\nExam Trap:\nFor discrete distributions with n scenarios at confidence alpha, the number of tail observations is n x (1 - alpha). If this is not an integer, interpolation rules apply. The FRM exam frequently tests whether students correctly identify which observations fall in the tail.\n\nPractice ES calculations in our FRM question bank.
Master Part I with our FRM Course
64 lessons · 120+ hours· Expert instruction
Related Questions
How is the swap rate curve constructed, and why does bootstrapping from deposit rates to swap rates matter for valuation?
Why did the industry shift to OIS discounting for collateralized derivatives, and how does it differ from LIBOR discounting?
How does a knock-in barrier option actually activate, and what determines its value before the barrier is breached?
How does linear interpolation work on a bootstrapped yield curve, and what artifacts does it introduce?
How does the cheapest-to-deliver switch option work in Treasury bond futures, and when does the CTD bond change?
Join the Discussion
Ask questions and get expert answers.