How is an arbitrage-free binomial interest rate tree calibrated to match market prices?
For CFA Level II, I need to understand how the binomial tree is built. My materials say it must be 'calibrated' to be arbitrage-free. What does calibration mean in practice? How do we ensure the tree prices on-the-run bonds correctly?
An arbitrage-free binomial interest rate tree is constructed so that it correctly prices all on-the-run benchmark bonds (typically Treasuries). Calibration is the process of adjusting the tree's rates until this condition holds.
Calibration Process (Step by Step):
Step 1: Set the 1-Year Rate
The current 1-year rate (r0) is directly observable. Suppose r0 = 4.00%.
Step 2: Calibrate Year 1 Rates
We need r1u and r1d such that the tree prices the 2-year on-the-run Treasury correctly.
Given: 2-year on-the-run coupon bond priced at par with coupon = 4.50%
Assume log-normal model: r1u = r1d x e^(2σ), where σ is the assumed volatility.
With σ = 15% and trial-and-error:
- r1d = 4.15%, r1u = 4.15% x e^(0.30) = 5.60%
Verification: Price the 2-year 4.50% bond using the tree:
- At node r1u: Value = (100 + 4.50) / 1.0560 = $99.05
- At node r1d: Value = (100 + 4.50) / 1.0415 = $100.34
- At node r0: Value = [0.5 x (99.05 + 4.50) + 0.5 x (100.34 + 4.50)] / 1.04
- = [103.55 x 0.5 + 104.84 x 0.5] / 1.04 = 104.195 / 1.04 = $100.19
If this does not equal par ($100), adjust r1d and repeat until it does.
Step 3: Calibrate Year 2 Rates
Repeat the process using the 3-year on-the-run bond, now solving for r2uu, r2ud, and r2dd with the constraint that adjacent rates are related by the volatility parameter.
Key Properties of the Calibrated Tree:
- Equal probability (0.5 up, 0.5 down) at each node
- Adjacent rates separated by e^(2σ)
- Every on-the-run bond prices to par
- The tree is 'arbitrage-free' because it matches observable market prices
Exam Tip: CFA Level II often asks you to use a given calibrated tree, not build one from scratch. But understand the calibration logic and know that the tree must reprice benchmark bonds correctly.
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