How do I interpret z-scores in hypothesis testing — and when should I use a z-test vs. a t-test?
I'm studying Quantitative Methods for CFA Level I and keep mixing up z-scores and t-scores. My textbook says to use z when the population variance is known, but in practice it seems like it's never known. Can someone clarify when I'd actually use each, and walk through interpreting a z-score in a real hypothesis test?
Great question — the z-score vs. t-test distinction trips up a lot of CFA candidates. Here's the clear breakdown:
What a Z-Score Represents A z-score measures how many standard deviations an observation (or sample mean) falls from the population mean. The formula is:
z = (X̄ − μ₀) / (σ / √n)
Where X̄ is the sample mean, μ₀ is the hypothesized population mean, σ is the known population standard deviation, and n is the sample size.
When to Use Z vs. T
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Worked Example: Nelton Industries claims its quarterly earnings growth averages 4.2%. You sample 36 quarters and find X̄ = 3.6% with a known σ = 2.4%.
- H₀: μ = 4.2%
- Hₐ: μ ≠ 4.2% (two-tailed)
- z = (3.6 − 4.2) / (2.4 / √36) = −0.6 / 0.4 = −1.50
At a 5% significance level (two-tailed), the critical values are ±1.96. Since |−1.50| < 1.96, we fail to reject H₀. The sample doesn't provide enough evidence that the true mean differs from 4.2%.
Key Exam Tips:
- A z-score of ±1.96 corresponds to a 95% confidence level (two-tailed) — memorize this.
- At ±2.58 you're at 99% confidence.
- With large samples (n ≥ 30), the t-distribution converges toward the z-distribution, so the choice matters less.
- The CFA exam will always specify whether σ is known — read the vignette carefully.
For more practice with hypothesis testing, explore our CFA Level I Quantitative Methods course.
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